Question

3x square + 11x + 30 solve it by splitting middle term

Answer 1

$\Huge{\red{\underline{\textsf{Answer}}}}$

$\implies\rm 3x^2+11x+30$

Multiple of last and first term:

3x² × 30 = 90x²

$\begin{array}{r | l}</p><p></p><p>2 & 90 \\</p><p></p><p>\cline{2-2} 3 & 45 \\</p><p></p><p>\cline{2-2} 3 & 15 \\</p><p></p><p>\cline{2-2} 5 & 5 \\</p><p></p><p>\cline{2-2} & 1</p><p></p><p>\end{array}$

So, we can write 90 = 6 × 15

$\because \\ 3 {x}^{2} + 11x + 30$

$\implies\rm 3x^2-6x+15x+30$

$\implies\rm 3x(x+2)+15(x+2)$

$\implies\rm (3x+15) (x+2)$

$\implies\rm 3(x+15) (x+2)$