Question

√3x square+2√3x+1=0 solve by formula method​

Answer 1

Answer:

Refer To The Attachment

Answer 2

Answer:

Hey!! Ur answer:

${( \sqrt{3x} )}^{2} + 2 \sqrt{3x} + 1 = 0 \\ > {( \sqrt{3x} )}^{2} + 1 \sqrt{3x} + 1 \sqrt{3x} + 1 = 0 \\ > \sqrt{3x} ( \sqrt{3x} + 1) + 1( \sqrt{3x} + 1) = 0 \\ = > ( \sqrt{3x} + 1)( \sqrt{3x } + 1) = 0$

Step-by-step explanation:

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