Question

3x square-2√6x+2 by factorisation method​

Answer 1

Answer:

Please refer to the attachment

Another method

3x^2 - 2 root 6 x +2

This is perfect square

(a+b) ^2

=(root 3x - root 2)^2

X= root 2/root 3

Answer 2

Answer:

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3x²-2√6x+2=0

3x²-√6x-√6x+2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

either (√3x-√2) or (√3-√2)=0

x=√2\√3 ,√2\√3

Step-by-step explanation:

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