3x square-2√6x+2 by factorisation method
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5
Answer:
Please refer to the attachment
Another method
3x^2 - 2 root 6 x +2
This is perfect square
(a+b) ^2
=(root 3x - root 2)^2
X= root 2/root 3
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Answered by
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Answer:
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3x²-2√6x+2=0
3x²-√6x-√6x+2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
either (√3x-√2) or (√3-√2)=0
x=√2\√3 ,√2\√3
Step-by-step explanation:
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