Question

3x square -2 root 6x +2=0 by completing sq method​

Answer 1

hey mate

here is the answer..

3x²-2√6x+2=0

(√3x)²-2.√3x.√2+(√2)²=0

[writing it in the form of a²-2ab+b²]

(√3x-√2)²=0

(√3x-√2)(√3x-√2)=0

by zero product rule,

x=√2/√3 (answer)