Question

3x square + 3 root 3 x + 2 = 0

Answer 1

Answer: x = $-1/\sqrt{3}$ or x = $-2/\sqrt{3}$

Step-by-step explanation:

3xsq. + 3root3x + 2 = 0

3xsq. + root3x + 2root3x + 2 = 0

root 3x (root 3x + 1) + 2 (root 3x + 1) = 0

(root 3x + 1)(root 3x + 2) = 0

root 3x = -1 or root 3x =-2

Therefore, x = $-1/\sqrt{3}$ or x = $-2/\sqrt{3}$

Answer 2

3X^2+3√3X+2=0

THIS IS IN THE FORM OF

aX^2+bX+C

so,

X= {-b±(√b^2-4ac)}/2a

here

b= 3√3

a= 3

c=2

so,

X=(-3√3±(√27-24))/(2×3)

X=(-3√3±√3)/6

SO Roots of the given equation are

$\frac{ - 3 \sqrt{3 } + \sqrt{3} }{6 }$

and

$\frac{ - 3 \sqrt{3 } - \sqrt{3} }{6}$

here to proceed ,take √3

common and then you will get

-√3/3

=-1/√3

and

-2√3/3

=-2/√3

so answer is -1/√3 and -2/√3

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