Math, asked by rooshanay, 4 months ago

3x square +5 =g(x) evaluate g(a +2)

Answers

Answered by Greizourexia
1

Answer:

g(a+2) = 3a^2+ 6a +17

Step-by-step explanation:

3x^{2} +5\\g(a+2)\\\\3(a+2)^{2}  + 5 = g(a+2)\\3(a^{2} +2a+4)  + 5 =g(a+2)\\\\3a^{2} + 6a+12 +5 = g(a+2)\\g(a+2) = 3a^{2} + 6a +17

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