Question

3x - $\dfrac{2}{y}$ = 5 and x + $\dfrac{4}{y}$ = 4 then find the value of x and y​

Answer 1

Answer:

Refer the attachment for your answer.

Answer 2

Given:-

• $3x - \frac{2}{y} = 5$
• $x + \frac{4}{y} = 4$

To Find:-

• x
• y

Solution:-

$3x - \frac{2}{y} = 5..(1)$

$x + \dfrac{4}{y} = 4..(2)$

Let

$\frac{1}{y} = a$

Then,

$3x - 2 a= 5..(3)$

$x + 4a= 4..(4)$

Now, Multiplying equation (3) with 2

$(3x - 2 a= 5) \times 2$

$= > 6x - 4a = 10..(5)$

Now, adding equation (4) and (5)

$x + 4a + 6x - 4a= 4 + 10$

$= > 7x = 14$

$= > x = \frac{14}{7}$

$= > x = 2$

Now Substituting the Value of x in Equation (4)

$= > x + 4a= 4$

$= > 2 + 4a = 4$

$= > 4a = 4 - 2$

$= > 4a = 2$

$= > a = \frac{2}{4}$

$= > a = \frac{1}{2}$

We Know that,

$\frac{1}{y} = a$

So,

$\frac{1}{y} = \frac{1}{2}$

$\therefore \: y = 2$

Hence, The Values are:-

• $\sf \: x = 2$
• $\sf \: y = 2$