Math, asked by Abhishekspradeep, 11 hours ago

3x=X/2-5 please answer fast​

Answers

Answered by Yuseong
9

Answer:

–2

Step-by-step explanation:

As per the provided information in the given question, we have a linear equation. We have to find the value of x.

Here, we'll use transposition method to solve this linear equation.

Basically, transposition method is used to solve a linear equation in one variable containing constants and variables. We just transpose the values from RHS to LHS by changing its arithmetic operators. In this way, we solve for the unknown value. During transposing the values, ( + ) changes to ( ) and vice-versa ; ( × ) changes to ( ÷ ) and vice-versa.

Now, coming back to the question. We have,

\longmapsto \rm { 3x = \dfrac{x}{2}- 5} \\

Taking the LCM in RHS and performing subtraction.

\longmapsto \rm { 3x = \dfrac{x - 10}{2}} \\

Transposing 2 from RHS to LHS. Its arithmetic operator will get changed.

\longmapsto \rm { 3x \times 2 = x - 10} \\

Performing multiplication in LHS.

\longmapsto \rm { 6x = x - 10} \\

Transposing x from RHS to LHS. Its arithmetic operator will get changed.

\longmapsto \rm { 6x - x = - 10} \\

Performing subtraction of the terms in LHS.

\longmapsto \rm { 5x = - 10} \\

Transposing 5 from LHS to RHS. Its arithmetic operator will get changed.

\longmapsto \rm { x = \cancel{\dfrac{- 10}{5}}} \\

Dividing –10 by 5.

\longmapsto \underline{\boxed{\bf { x = - 2}}} \; \bigstar \\

Therefore, the value of x is 2.

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