Question

3x(x)-2√6x+2=0 solve by factorisation method

Answer 1

$3x^2 - 2\sqrt{6}x + 2 = 0$
$3x^2 - \sqrt{6}x - \sqrt{6}x + 2 = 0$
$\sqrt{3}x(\sqrt{3}x - \sqrt{2}) - \sqrt{2}(\sqrt{3}x - \sqrt{2}) =0$
$(\sqrt{3}x - \sqrt{2})(\sqrt{3}x - \sqrt{2}) = 0$
$\sqrt{3}x - \sqrt{2} = 0$
$\sqrt{3}x = \sqrt{2}$
$x = \frac{\sqrt{2}}{\sqrt{3}}$
$x = \sqrt{\frac{2}{3}}$

I have used middle term factorization method...