Question

3x (x+2) and 8 are the
continuous terms of an A.P.
Find its
fourth
with term​

Answer 1

Answer:

18

Step-by-step explanation:

Given an AP such that,

3x , x+2 and 8 are consecutive terms of it.

To find the fourth term.

We know that,

If a, b and c are consecutive terms of an AP, then the mean of first and third term is equal to the second term.

Therefore, we will get,

• (a+c)/2 = b

Thus, in the given question, we get,

=> (3x+8)/2 = x+2

=> 3x + 8 = 2(x+2)

=> 3x + 8 = 2x + 4

=> 3x - 2x = 4 - 8

=> x = -4

Therefore, the terms are,

3x = 3(-4) = -12

x+2 = -4 + 2 = -2

And 8

Now, we have,

• First term, a = -12
• Common Difference, d = -2 -(-12) = 10

Thus, we have,

=> Fourth term = a + 3d

=> Fourth term = -12 +3(10) = 30-12 = 18

Hence, the fourth term is 18.