Question

-3x+x/3x+x=6
Solve for x​

Answer 1

Answer:

$\dfrac{-3x+x}{3x+x}=6\quad :\quad \mathrm{No\:Solution}$

Step-by-step explanation:

$\dfrac{-3x+x}{3x+x}=6$

$\mathrm{Simplify\:}\dfrac{-3x+x}{3x+x}$

$\dfrac{-3x+x}{3x+x}$

$\mathrm{Add\:similar\:elements:}\:-3x+x=-2x$

$=\dfrac{-2x}{3x+x}$

$\mathrm{Add\:similar\:elements:}\:3x+x=4x$

$=\dfrac{-2x}{4x}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \dfrac{-a}{b}=-\dfrac{a}{b}$

$=-\dfrac{2x}{4x}$

$\mathrm{Cancel\:the\:common\:factor:}\:2$

$=\dfrac{x}{2x}$

$\mathrm{Cancel\:the\:common\:factor:}\:x$

$=-\dfrac{1}{2}$

$-\dfrac{1}{2}=6$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$-\dfrac{1}{2}\cdot \:2=6\cdot \:2$

$\mathrm{Simplify}$

$-1\neq12$

$\mathrm{The\:sides\:are\:not\:equal}$

$\mathrm{No\:Solution}$