Math, asked by bunny2488, 1 year ago

3x (x+y-2)=2y;y(x+y-1)=9x​


bunny2488: please give all steps

Answers

Answered by prabhjotbrar00
6

Answer:

3x(x + y - 2) = 2y

y(x + y - 1) = 9x

3x^2 + 3xy - 6x = 2y

xy + y^2 - y = 9x

2xy + 2y^2 - 18x = 2y

3x^2 + 3xy - 6x = 2xy + 2y^2 - 18x

3x^2 + xy + 12x - 2y^2 = 0

Solution:

x = -96/25, y = -24/25Step-by-step explanation:


bunny2488: how x andy values came
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