3x (x – y – Z) + 3y (x – y + z) + 32 (x + y – z) from 3 (x + y) (x – y) + 3z (2y + z)
z) and 3y (2z + x + x2)
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Given system of linear equations are
2x+3y+3z=5
x−2y+z=−4
3x−y−2z=3.
Represent it in matrix form
⎣⎢⎢⎡2133−2−131−2⎦⎥⎥⎤⎣⎢⎢⎡xyz⎦⎥⎥⎤=⎣⎢⎢⎡5−43⎦⎥⎥⎤ which is in the form of AX=B
A=⎣⎢⎢⎡2133−2−131−2⎦⎥⎥⎤
∣A∣=10+15+15=40=0
∴ A−1 exists
To find adjoint of A
A11=5
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