Math, asked by yanakakkar7, 9 months ago

3x(x-y-z) + 3y(x-y+z) + 3z(x+y-z) from 3(x+y)(x-y) + 3z12y+z)​

Answers

Answered by vishakha0987
2

Step-by-step explanation:

(3x – y + z) + (x + y – 3z) – (x – 2y – z). = 3x – y + z + x + y – 3z – x + 2y + z. = 3x + x – x – y + y + 2y + z + z – 3z. = 3x + 2y – z ...

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