3x+y=0, x-y=5 substitution method
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3x+y=0,
x-y=5
x=y+5
3x+y=0,
3(y+5)+y=0
3y+15+y=0
4y+15=0
4y=-15
y=-15/4
3x+y=0,
3x-15/4=0
(12x-15)/4=0
12x-15=0
12x=15
x=15/12
x=4/3
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