Question

3x–y=0, x–y+6=0,Solve the given pairs of linear equations by the method of substitution.

Answer 1

Answer :

Given equations are

3x - y = 0 ...(i)

x - y + 6 = 0 ...(ii)

From (i), we get

y = 3x and substituting this value in (ii), we get

x - 3x + 6 = 0

or, 2x = 6

or, x = 3

Now, putting x = 3 in (i), we get

y = 3 (3) = 9

Therefore, the required solution be

x = 3 and y = 9

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Answer 2

Solution :

3x - y = 0

=> y = 3x ---( 1 )

x - y + 6 = 0 ----( 2 )

Substitute y = 3x in equation ( 2 ),

we get

x - 3x + 6 = 0

=> -2x = -6

=> x = ( -6 )/( -2 )

=> x = 3

put x = 3 in equation ( 1 ) , we get

y = 3×3

=> y = 9

Therefore ,

( x , y ) = ( 3 , 9 )

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