Question

3x+y+1=0,2x-3y+8=0 by substitution

Answer 1

Answer:

Step-by-step explanation:

3x+y+1=0. (1)

2x-3y+8=0 (2)

Multiplying equation (1) with 3

9x+3y+3=0 (3)

Add (2) &(3)

We will get x= -1

Substitute x= -1 in eq (1)

We will get y=2

Hence, x= -1 & y=2

Hope this will help you..!

Answer 2

Answer:

Given:

Two equations are

3x+y+1=0 and

2x-3y+8=0

Solving Question:

 substitution method : in this method we substitute the values of the variables  in both of the equation so as to find the values of it

3x+y+1=0

⇒ 3x+y = -1 ...........equ(1)

2x-3y+8 = 0

⇒ 2x - 3y = -8 ..........equ(2)

Solution:

Tke equ(1)

⇒ 3x + y = -1

or, y = -1 -3x .........equ(3)

substitute the equ(3) in equ(2)

⇒ 2x -3y = -8

⇒ 2x -3(-1 -3x) = -8

⇒ 2x +3 +9x = -8

⇒ 11x +3 = -8

⇒ 11x = -11

⇒ x = -1

substitute this value in equ(3)

⇒ y = -1 -3x

⇒ y = -1 -3*-1

⇒ y = -1+3

or, y= 2

Thus, the values of 'x' = -1 and 'y' = 2