Question

3x + y = 1 , (2k-1)x + (k-1)y = 2k +1 . Find the value of k

Answer 1

Answer:

bro here is the answer. hope it helps

Answer 2

Given:- 3x+y=1

Also, (2k-1)x+(k-1)=2k+1

Both of them can be written in the form of equation as,

3x+y-1=0 ...... (Equation1)

(2k-1)x+(k-1)y-(2k+1)=0......(Equation 2)

We know that for No Solution we have

a1/a2=b1/b2≠c1/c2.

From two of the above mentioned equations we have ,

a1=3,b1=1,C1=-1

a1=3,b1=1,C1=-1a2=(2k+1),b2=(k-1),c2=-(2k+1)

Now substituting the values of a,b and c we get,

→3/(2k+1)=1/(k-1)

By cross multiplication we get,

→3(k-1)=1(2k-1)

→3k-3=2k-1

→3k-2k=(-1)+(3)

→k=2.

Hence, the required value of k= 2