3x+y=1,(2x-1)x+(k-1)y=(2k-1) value of k
a)-7
b)2
c)7
d)-2
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3
Answer:
I think this is the answer. Sorry if wrong. I tried to help you.
Step-by-step explanation:
3x + y = 1
= x = 1 – y / 3
So, 1 – y / 3 + y = 1
= 1 – y + 3y / 3 = 1 + 2y / 3 = 1
= 1 + 2y = 3
= 2y = 3 – 1 = 2
= y = 2/2 = 1
x = 1– y / 3 = 1 – 1 / 3 = 0 / 3 = 0
Now, ( 2x – 1 ) x + ( k – 1 ) y = 2k – 1
= x × x +( ky – y ) = x² + k = 2k – 1
= x² + k = 2k – 1
= x² + 1 = 2k – k
= x² + 1 = k
= 0² + 1 = k
= 0 + 1 = k
= k = 1 + 1 = 2
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