Math, asked by krishnamoorthy2006, 8 months ago

3x+y=13 and x-3y+9=0 solve by cross multiplication

Answers

Answered by wwwramanakumari
1

Answer:

Step-by-step explanation:

3x+y=13------1

x-3y=-3-------2

Multiply 3 to eq2

3x-9y=-9--------3

Solve eq1 and eq3

3x+y=13

3x-9y=-9

--------------

10y=22

Y=2.2

Sub y=2.2 in eq1

3x+2.2=13

3x=10.8

x=3.4

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