3x+y=13 and x-3y+9=0 solve by cross multiplication
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Answer:
Step-by-step explanation:
3x+y=13------1
x-3y=-3-------2
Multiply 3 to eq2
3x-9y=-9--------3
Solve eq1 and eq3
3x+y=13
3x-9y=-9
--------------
10y=22
Y=2.2
Sub y=2.2 in eq1
3x+2.2=13
3x=10.8
x=3.4
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