(3x+y=15)-(x+2y=10) then find the value of x and y
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Answer:
3x +y=15
x-2y=10
(multiply 2nd equation by 3 )
we get
3x-6y=30
now subtract 1 equation from 3rd equation
we get
3x-6y=30
-3x+y=15
5y=15
y=15/5
y=3
now put y=3 in equation 1st we get
3x+3=15
3x=15-3
3x=12
x=12/3
x=4
therefore
x=4 and y=3
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