3x-y-2=0 ,2x+y=8 solve by substitution method
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srushti81:
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3x - y = 2
Y = 3x - 2...... (1)
2x + y = 8
2x + (3x - 2) = 8
2x + 3x - 2 = 8
5x = 8+2
5x = 10
X = 10/5
X= 2
Now putting rhe values in (1)
Y = 3(2) -2
Y= 6-2
Y= 4
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