3x+y =2 , 2x-3y =5 by substitution
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3x+y=2‐----------(1)
2x-3y=5--------(2)
by transposition in (1)
we get,
3x=2-y
therefore,
x=(2-y)/3---------(3)
Now, putting (3) in (2) we get,
2(2-y)/3 - 3y=5
=(4-2y/3) - 3y=5
= (4-2y-9y) / 3 = 5
= (4-11y) / 3 = 5
= (4-11y) = 15
This gives us,
-11y = 11
therefore, y = -1
therefore, 3x = 2-y or
3x = 3
therefore, x = 1
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