Question

3x-y=2;2x-y=3
@Brainlybutterfliee can u please solve it

Answer 1

Answer:

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Answer 2

${\large{\pmb{\sf{\underline{RequirEd \: solution...}}}}}$

${\bigstar \:{\pmb{\sf{\underline{Explanation...}}}}}$

⠀⠀⠀⠀⠀⠀There are two equations given, we have to solve these equations. Let us solve these equations by graphical method. Firstly let's assume that

$\sf Assumptions \: (Let) \begin{cases} & \sf{3x - y = 2 \: as \: \bf{Equation \: 1}} \\ \\ & \sf{2x - y = 3 \: as \: \bf{Equation \: 2}} \end{cases}$

Now let's put x as 0 in Equation 1

⇢ 3x - y = 2

⇢ 3(0) - y = 2

⇢ 0 - y = 2

⇢ -y = 2

⇢ y = -2

• ∴ Coordinates are (0,-2)

Now let's put y as 0 in Equation 1

⇢ 3x - y = 2

⇢ 3x - 0 = 2

⇢ 3x = 2

⇢ x = 2/3

⇢ x = 0.66

⇢ x ≈ 0.7

• ∴ Coordinates are (0.7,0)

Now let's put x = 0 in Equation 2

⇢ 2x - y = 3

⇢ 2(0) - y = 3

⇢ 0 - y = 3

⇢ -y = 3

⇢ y = -3

• ∴ Coordinates are (0,-3)

Now let's put y = 0 in Equation 2

⇢ 2x - y = 3

⇢ 2x - 0 = 3

⇢ 2x = 3

⇢ x = 3/2

⇢ x = 1.5

• ∴ Coordinates are (1.5,0)

They intersect at (-1,-5)

${\large{\pmb{\sf{\underline{Learn \: More...}}}}}$

The system used for describing the position of a point in the plane is known as cartesian system.

Relation between the signs of the coordinates of a point and the quadrant of a point in which it lie.

1) If the point is in the first quadrant then the point will be in the form of (+,+) since the 1st quadrant is enclosed by the positive x-axis and positive y-axis

2) If the point is in the second quadrant then the point will be in the form of (-,+) since the 2nd quadrant is enclosed by the negative x-axis and positive y-axis

3) If the point is in the third quadrant then the point will be in the form of (-,-) since the 3rd quadrant is enclosed by the negative x-axis and negative y-axis

4) If the point is in the fourth quadrant then the point will be in the form of (+,-) since the 4th quadrant is enclosed by the positive x-axis and negative y-axis

Kindly see this concept from attachment 4th