Question

3x-y=2 & x+2y=3 by subsititution method​

Answer 1

Answer:

$\bold\purple{{3x - y = 2}}$

$\bold\purple{{y = 3x - 2}}$

$\green{Now, \: x + 2y = 3}$

$\green{x + 2(3x - 2) = 3}$

$\green{x + 6x - 4 = 3}$

$\green{7x = 3 + 4}$

$\green{7x = 7}$

$\green{x = \frac{7}{7}}$

$\green{x = 1}$

$\blue{y = 3x - 2}$

$\blue{y = 3(1) - 2}$

$\blue{y = 3 - 2}$

$\blue{y = 1}$

$\red{So, \: x = 1 \: and \: y = 1.}$

Answer 2

Answer:

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3x-y=2

y=3x-2.......(1)

now, x+2y=3.......(2)

sub.(1) in (2)

x+2(3x-2)=3

x+6x-4=3

7x=7

x=7/7=y=3×1-2

y=1

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