3x+y-3=0;2x+2y=0 prove that the following equation have no solution
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3x+y-3=0 ...(1)
2X+2Y=0 ...(2)
now convert first equation in 1st equation ....
a+b=c
3x+y=3 ....(3)
2x+2y=0 ....(2)
(multiply 3rd equation by 2
and 2nd equation by 3rd)....
6x+2y=6....(4)
6x+6y=0....(5)
--------------------
0x-4y=6
-4y=6
y=6upon -4
y=-3upon2 (put in 2nd equation)
2x+2y=0
2x+2×(-3upon2)=0
cancel 2 and 2
now we get
2x-3=0
2x=3
x=3upon 2.....
I think it will help you
3x+y-3=0 ...(1)
2X+2Y=0 ...(2)
now convert first equation in 1st equation ....
a+b=c
3x+y=3 ....(3)
2x+2y=0 ....(2)
(multiply 3rd equation by 2
and 2nd equation by 3rd)....
6x+2y=6....(4)
6x+6y=0....(5)
--------------------
0x-4y=6
-4y=6
y=6upon -4
y=-3upon2 (put in 2nd equation)
2x+2y=0
2x+2×(-3upon2)=0
cancel 2 and 2
now we get
2x-3=0
2x=3
x=3upon 2.....
I think it will help you
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