3x-y=3,9x-3y=9 by substitution method
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Answered by
0
Answer:
3x – y = 3 and 9x – 3y = 9 are the two equations.
From 1st equation, we get,
x = (3+y)/3
Now, substitute the value of x in the given second equation to get,
9(3+y)/3 – 3y = 9
⇒9 + 3y – 3y = 9
⇒ 9 = 9
Therefore, y has infinite values and since, x = (3+y) /3, so x also has infinite values.
Answered by
0
Answer:
x ∈ R
Step-by-step explanation:
make y subject of the formula in the first equation:
y= (3-3x)/-1
substitute y with what y has been equated to and solve from there:
THE VALUE OF X IS IN PARAMETRIC FORM (it is independent/infinite)
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