3x-y=3and9x-3y=9 by substitution method
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Elimination by substitution :-
9x-3y=9 -------> [ 1 ]
3x - y = 3 ------> [ 2 ]
3x = 3 + y
x = [3 + y]/ 3
Put this value in equation [1 ]
9 × { [3 + y]/ 3 } - 3y = 9
[27+9 y ] / 3 - 3y = 9
9 [ 3 + 1 y ] / 3 = 9
3 [ 3 + 1 y ] = 9
9 + 3y = 9
3y = 9 - 9
3y = 0
y = 0
x = y + 3 / 3
= 0 + 3 / 3
= 1
Hence ,
x = 1 , y = 0
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