(3x-y) (3x+y+y^2)-(2x+3y) (x^2+x-1)
Answers
Answer:
−2x3−3x2y+3xy2−y3+7x2−3xy−y2+2x+3y
Step-by-step explanation:
Let's simplify step-by-step.
(3x−y)(3x+y+y2)−(2x+3y)(x2+x−1)
Distribute:
=(3x)(3x)+(3x)(y)+(3x)(y2)+(−y)(3x)+(−y)(y)+(−y)(y2)+−2x3+−3x2y+−2x2+−3xy+2x+3y
=9x2+3xy+3xy2+−3xy+−y2+−y3+−2x3+−3x2y+−2x2+−3xy+2x+3y
Combine Like Terms:
=9x2+3xy+3xy2+−3xy+−y2+−y3+−2x3+−3x2y+−2x2+−3xy+2x+3y
=(−2x3)+(−3x2y)+(3xy2)+(−y3)+(9x2+−2x2)+(3xy+−3xy+−3xy)+(−y2)+(2x)+(3y)
=−2x3+−3x2y+3xy2+−y3+7x2+−3xy+−y2+2x+3y
Answer:
=−2x3−3x2y+3xy2−y3+7x2−3xy−y2+2x+3y
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10th
Maths
Pair of Linear Equations in Two Variables
Algebraic Solution of a Pair of Linear Equations
If 3x - 2y = 5 and 3y - 2x ...
MATHS
If 3x−2y=5 and 3y−2x=3 then find the value of (x+y).
MEDIUM
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ANSWER
3x−2y=5............ (1)
3y−2x=3
−2x+3y=3
Multiply (1) by 2 & eq (2) by 3
6x−4y=10..........(3)
−6x+9y=19..........(4)
_______________
Adding eqn (3) and (4), we get
6x−4y=10
−6x+9y=19
___________
5y=1
y=
5
1
Putting the value in
6x−
5
4
=10
6x=10+
5
4
=
5
54
x=
5×6
54
=
5
9
x=
5
9
Now x+y=
5
9
+
5
1
=
5
10
=2$$
x+y=