Question

3x+y/4=7/4 and x/6+2y/3=-5/3 solve by eliminations or substitution method

Answer 1

3x+y/4=7/4 and x/6+2y/3=-5/3
(12x+y)4=7*4 and (x+4y)3=-5*6
48x+4y=28 and 3x+12y=-30
Multiplying 3x+12y =-30 by 16
48x+198y=-360 (using elimination)
48x+4y=28
194y=-331
y=1.7
Putting value of y in 3x +12y=-30
3x+12*1.7=-30
3x+20.4=-30
3x=-30-20.4
3x=-50.4
x=-16.8