3x-y=4and 2x-y=2 by subtitution method
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2
3x - y =4
x =( 4+y)/3
Now putting the value of x in the other equation,
2 (4+y)/3 - y = 2
(8+2y)/3 -y = 2
(8+2y -3y)/3 = 2
8 - y = 2 x3
8-y = 6
-y = 6-8
-y = -2
y =2
Now putting the value of y in the first equation,
3x -2 = 4
3x = 4+2
3x = 6
x = 2
Therefore, x = 2 ,y =2
x =( 4+y)/3
Now putting the value of x in the other equation,
2 (4+y)/3 - y = 2
(8+2y)/3 -y = 2
(8+2y -3y)/3 = 2
8 - y = 2 x3
8-y = 6
-y = 6-8
-y = -2
y =2
Now putting the value of y in the first equation,
3x -2 = 4
3x = 4+2
3x = 6
x = 2
Therefore, x = 2 ,y =2
kirat7:
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Answered by
0
3x-y =4 ⇒3x-4 =y---(1)
2x-y =2 --(2)
put y= 3x-4 in (2)
2x-(3x-4) =2
2x-3x+4 =2
-x +4 =2
-x=2-4
-x=-2
therefore
x=2
put x=2 in (1)
3x-4=y
3*2-4 =y
6-4=y
2=y
y=2
therefore
x=2, y=2
2x-y =2 --(2)
put y= 3x-4 in (2)
2x-(3x-4) =2
2x-3x+4 =2
-x +4 =2
-x=2-4
-x=-2
therefore
x=2
put x=2 in (1)
3x-4=y
3*2-4 =y
6-4=y
2=y
y=2
therefore
x=2, y=2
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