Question

3x + y - 5 = 0
2x - y - 5 = 0​

Answer 1

★ GivEn EquAtiOnS :-

• 3x + y - 5 = 0
• 2x - y - 5 = 0

★ To FinD :-

• values of x and y

★ SoLutiOn :-

On Adding both the sides of the Equations,

We get

$\sf{3x + y - 5 + 2x - y - 5 = 0 + 0}$

$\sf{3x + 2x + y - y - 5 - 5 = 0 }$

$\sf{5x - 10= 0 }$

$\sf{5x = 10 }$

$\sf\red{\underline{\therefore \: x = 2 }}$

Now, putting the value of x in any one of the Equations, we have

$\sf{3x + y - 5 = 0 }$

$\sf{(3 \times 2) + y - 5 = 0 }$

$\sf{6+ y - 5 = 0 }$

$\sf{y + 1 = 0 }$

$\sf\red{\underline{\therefore \: y = - 1 }}$

Which are the required values of x and y.

Answer 2

Answer:

★ GivEn EquAtiOnS :-

3x + y - 5 = 0

2x - y - 5 = 0

★ To FinD :-

values of x and y

★ SoLutiOn :-

On Adding both the sides of the Equations,

We get

$\sf{3x + y - 5 + 2x - y - 5 = 0 + 0} \\ </p><p></p><p>\sf{3x + 2x + y - y - 5 - 5 = 0 } \\ </p><p></p><p>\sf{5x - 10= 0 } \\ </p><p></p><p>\sf{5x = 10 } \\ </p><p></p><p>\sf\red{\underline{\therefore \: x = 2 }}$

Now, putting the value of x in any one of the Equations, we have

$\sf{3x + y - 5 = 0 } \\ </p><p></p><p>\sf{(3 \times 2) + y - 5 = 0 } \\ </p><p></p><p>\sf{6+ y - 5 = 0 } \\ </p><p></p><p>\sf{y + 1 = 0 } \\ </p><p></p><p>\sf\red{\underline{\therefore \: y = - 1 }} </p><p>$

Which are the required values of x and y.