Question

3x-y=5 and 4x-3y=-1 by substitution method

Answer 1

Step-by-step explanation:

3x-y=5

y= 3x-5

4x-3y=-1

4x-3(3x-5)=-1

4x-9x+15+1=0

-5x+16=0

5x=16

x=16/5

substitute x=16/5 in 3x-y=5

3(16/5)-y=5

48/5-5=y

48-25/5=y

y=23/5

x=16/5

y=23/5

Answer 2

Answer:

x = 16/5 , y = 23/5

Step-by-step explanation:

3x - y = 5 -----------(1)

4x - 3y = -1 -----------(2)

from eq 1

3x - y = 5

3x - 5 = y ----------(3)

put eq 3 in eq 2

4x - 3y = -1

4x - 3(3x - 5) = -1

4x - 9x + 15 = -1

-5x + 15 = -1

-5x = - 1 - 15

-5x = -16

5x = 16

x = 16/5

put x in eq 1

3x - y = 5

3(16/5) - y = 5

48/5 - y = 5

48/5 - 5 = y

(48 - 25)/5 = y

23/5 = y