3x=y+5 and 5x-5y=11 by elimination method
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Step-by-step explanation:
above eqn can be written as
3x-y=5 ....(1)
5x-5y=11 ....(2)
multiplying by 5 in eqn (1) we get
15x-5y=25
5x-5y=11
after subtracting we get
10x=14
:::x=7/5
after putting the value of x in eqn (2) we get
7-5y=11
5y= -4
y= -4/5
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