3x -y=5 and x+2y=4 solve graphically
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x+2y=4 …(i)
2y=4−x
y=(4−x)/2
When x=0,y=(4−0)/2=4/2=2
When x=2,y=(4−2)/2=2/2=1
When x=4,y=(4−4)/2=0/2=0
x= 0 ,2 ,4
y= 2 ,1 ,0
Mark the above points on graph. Join them.
3x−2y=4 ..(ii)
2y=3x−4
y=(3x−4)/2
When x=0,y=(3×0−4)/2=(0−4)/2=−4/2=−2
When x=2,y=(3×2−4)/2=(6−4)/2=2/2=1
When x=4,y=(3×4−4)/2=(12−4)/2=8/2=4
Mark the above points on graph. Join them.
x= 0 ,2 ,4
y= −2 ,1 ,4
It is clear from the graph that the two lines intersect at (2,1).
So the solution of the given equations are x=2 and y=1.
The area of the triangle formed by these lines and Xaxis=1/2×base×height
=1/2×2.7×1
=1.35sq. units
Hence area of the triangle is 1.35sq.unite
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