Math, asked by nishakumari12520199, 9 months ago

(3x+y-5)dy-2(x+y-1)dx=0

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Answered by Anonymous

3

Answer: dy/dx=(3x+y-5)/2(x+y-1)

Step-by-step explanation:(3x+y-5)dy-2(x+y-1)dx=0

(3x+y-5)dy = 2(x+y-1)dx

dy/dx = (3x+y-5)/2(x+y-1)

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