Question

3x-y-5 equal to 0, 6x-2y+k equal to 0 ( k not equal to 0)

Answer 1

Step-by-step explanation:

The given system of equations:

3x - y - 5 = 0 ….(i)

And,

6x - 2y + k = 0 ….(ii)

These equations are of the following form:

a1x+b1y+c1 = 0,

a2x+b2y+c2 = 0

where, a1 = 3, b1= -1, c1 = -5

and

a2 = 6, b2 = -2, c2 = k

In order that the given system has no solution, we must have:

Hence, equations (i) and (ii) will have no solution if k ≠ -10.

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Answer 2

Answer:

k = -10

Step-by-step explanation:

In frist equation,  

     3x-y-5=0

     3x-5 = y     ------(i)

In second equation,

     6x - 2y + k = 0

     6x -2(3x-5) +k =0       from (i)

     6x - 6x + 10 +k =0

     k = -10

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