3x=y+5,x+y=11 by substitute method
Answers
3x=y+5
x=(y+5)/3...(1)
x+y=11...(2)
Substituting the value of x in equation (2)
y+5/3 +y=11
(y+5+3y)=33
5+4y=33
4y=33-5
4y=28
y=28/4
y=7
Substituting y=7
x+7=11
x=11-7
x=4
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The given systems of equations is
3x-y =5 .....(i)
x+y =11 ... .(ii)
From (ii), we get
y = 11-x
Substituting y=(11- x) in (i),we get
3x-(11-x) =5
3x-11 +x =5
4x -11 =5
4x = 5+11
4x =16
x =4
Substituting x=4 in (ii),we get
x+y = 11
4+y =11
y = 11-4
y = 7
Hence , the solution is x =4, y = 7.
Hope the answer helps you.