Question

3x-(y+7)/11+2=10 , 2y +(x+11)/7=10

Answer 1

Answer:

Step-by-step explanation:

3x- (y-7)/11 +2 =10  

multiply both sides by 11  

33x -(y-7) + 22 = 110  

33x-y+7+22=110  

33x-y +29 = 110  

33x-y = 81 --------------(1)  

2y+(x+11)/7 = 10  

multiply both sides by 7  

14y +(x+11) = 70  

14y +x + 11 = 70  

x+14y = 59 ------------(2)  

33x-y = 81 --------------(1)  

x+14y = 59 ------------(2)  

Multiply equation (1) by 14  

462x-14y = 1134  

x+14y = 59 --------(2)  

add:26124/6482  

463 x = 1193  

x= 1193/463  

substitute x=1193/463 into equation (2)  

1193/463 + 14y = 59  

multiply both sides by 463  

1193 + 6482y = 27317  

6482y = 26124  

y = 26124 / 6482  

divide the numerator and the denominator by 14  

y = 1866/ 463  

x= 1193/463  

y = 1866/ 463

hope it is helpful

Answer 2

Answer:

y = 40/7 and x = 293

Step-by-step explanation:

3x-y-7/11+2=10

3x-y=10*13

3x-y=130+7

3x-y=137-------equcation no. (1)

then,

2y+x+11=10*7

arrange,

x+2y=70-11

x+2y=59-------equcation no. (2)

now

from equcation 1 and 2 ,

3x-y=137---- x 1

x+2y=59---- x 3

or, 3x - y = 137

3x+6y= 177

for subtracting

- 7y = - 40

y = 40/7

putting the value of y on 2

then,

x + 2y = 59

or, x + 2*40/7 =59

or, x + 2*40 =59*7

or, x + 120 = 413

or, x = 413 - 120

or, x = 293

hence, x = 293 and y = 40/7