Math, asked by golumanjit, 11 months ago

3x-y+7/11+2=10 2y+x+11/7=10​


golumanjit: please help me

Answers

Answered by santy2
2

Answer:

x = 1.60

y = 2.56

Step-by-step explanation:

These are simultaneous equations.

We rewrite the equations below :

3x - y + 7/11 + 2 = 10

We multiply through by 11 to get :

33x - 11y + 7 + 22 = 110

33x - 11y = 110 - 7 - 22

33x - 11y = 81

33x - 11y = 81……………1)

2y + x + 11/7 = 10

Multiply through by 7:

14y + 7x + 11 = 70

14y + 7x = 70 - 11

7x + 14y = 59…………………2)

We solve 1 and 2 simultaneously as follows:

33x - 11y = 81

7x + 14y = 59

We multiply equation 1 by 7 and equation 2 by 33 to get.

231x - 77y = 567

231x + 462y = 1947

Subtract equation 1 from 2:

539y = 1380

y = 2.56

We substitute this in equation 1 to get x as follows:

33x - 11 × 2.56 = 81

33x = 81 - 28.16

33x = 52.84

x = 52.84/33

x = 1.60

These are approximate values of x and y.


parth57049: wrong answer
Answered by knjroopa
15

Answer:

x = 3, y = 4

Step-by-step explanation:

Given 3 x -  y + 7 / 11  + 2 = 10  and  2 y + x + 11 / 7 = 10

After simplifying we get

33 x – y – 7 + 22 = 110

33 x – y + 15 = 110

33 x – y = 95---------------(1)

Second equation will be

14 y + x + 11 = 70

X + 14 y = 59------------(2)

Multiplying second equation by 33 we get

33 x + 462 y = 1947 -----------(3)

By solving 1 and 3 we get

33 x – y = 95

33 x + 462 y = 1947

-----------------------------

- 463 y  = - 1852  

 Y = 4

33 x – y = 95

33 x – 4 = 95

33 x = 99

X = 3

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