Question

3x-(y+7)/11+2=10 , 2y+(x+11)/7=10
Solve for x and y

Answer 1

$\textbf{Given:}$

$3x-\frac{(y+7)}{11}+2=10$

$2y+\frac{x+11}{7}=10$

$\textbf{To find:}$

$\text{Solution of given equations}$

$\textbf{Solution:}$

$\text{The given equations can be written as}$

$3x-\frac{(y+7)}{11}+2=10$

$\frac{33x-y-7}{11}=8$

$33x-y-7=88$

$\implies\boxed{\bf\,33x-y-95=0}$.......(1)

$2y+\frac{x+11}{7}=10$

$14y+x+11=70$

$\implies\boxed{\bf\,x+14y-70=0}$.......(2)

$\text{Now, solve the equations (1) and (2) by cross multiplication rule}$

$\dfrac{x}{59+(95)(14)}=\dfrac{y}{-95+(33)(59)}=\dfrac{1}{(33)(14)+1}$

$\dfrac{x}{1389}=\dfrac{y}{1852}=\dfrac{1}{463}$

$\implies\dfrac{x}{1389}=\dfrac{1}{463}\;\text{and}\;\dfrac{y}{1852}=\dfrac{1}{463}$

$\implies\,x=\dfrac{1389}{463}\;\text{and}\;y=\dfrac{1852}{463}$

$\implies\,x=3\;\text{and}\;y=4$

$\therefore\textbf{The solution is x=3 and y=4}$

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Answer 2

$\huge{\underline{\tt{QUESTION:-}}}$

Solve for x and y :-

3x-(y+7)/11+2=10 , 2y+(x+11)/7=10

$\huge{\underline{\tt{ANSWER:-}}}$

Refer to the attachments !