Math, asked by kisjorm, 9 months ago

3x - y + 7/11 + 2 =10,2y + X + 11 by 7 is equal to 10​

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Answered by rishavrishav1111
1

Answer:

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rishavrishav1111

Secondary School Math 5+3 pts

3x-(y+7)/11+2=10 , 2y+(x+11)/7=10

Solve for x and y

by Ananya0000 09.09.2018

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Answers

arshbilga123

Arshbilga123Expert

3x- (y-7)/11 +2 =10

multiply both sides by 11

33x -(y-7) + 22 = 110

33x-y+7+22=110

33x-y +29 = 110

33x-y = 81 --------------(1)

2y+(x+11)/7 = 10

multiply both sides by 7

14y +(x+11) = 70

14y +x + 11 = 70

x+14y = 59 ------------(2)

33x-y = 81 --------------(1)

x+14y = 59 ------------(2)

Multiply equation (1) by 14

462x-14y = 1134

x+14y = 59 --------(2)

add:26124/6482

463 x = 1193

x= 1193/463

substitute x=1193/463 into equation (2)

1193/463 + 14y = 59

multiply both sides by 463

1193 + 6482y = 27317

6482y = 26124

y = 26124 / 6482

divide the numerator and the denominator by 14

y = 1866/ 463

x= 1193/463

y = 1866/ 463

hope it is helpful

Answered by aryandhar019
0

Step-by-step explanation: 3x - y + 29/11 = 10 (1)

2y + x + 11 /7 = 10

2y + x = 59/7 (2)

multiply (1) by 2

we get

6x - 2y = 162/11 (3)

now add (2) and (3)

we get

7x = 1783/11

x= 1783/77 (4)

put (4) in (2)

we get

2y + 1783/77 = 59/7

y = -576/77

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