Question

3x - y+7/11 +2 and 2y +( x+11)/7 = 10

Answer 1

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

3x - (y + 7)/11 + 2 = 10 …………...(a)

2y + (x + 11)/7 = 10 …………...(b)

Now,

From (a) we have

{(11 × 3x - (y + 7) + 2 × 11}/11 = 10

33x - y - 7 + 22 = 10 × 11

33x - y + 15 = 110

33x - y = 110 - 15

33x - y = 95

-y = 95 - 33x

y = 33x - 95 ………….(c)

Also

From (b) we have,

{(7 × 2y + (x + 11)}/7 = 10

14y + x + 11 = 7 × 10

14y + x + 11 = 70

14y + x = 70 - 11

14y + x = 59 ………..(d)

Putting value of y from (c) in (d) :-

14(33x - 95) + x = 59

462x - 1330 + x = 59

463x = 59 + 1330

463x = 1389

x = 1389/463

x = 3

Now,

Substituting value of x in (c),

y = 33x - 95

y = 33 × 3 - 95

y = 99 - 95

y = 4

Therefore,

x = 3 & y = 4