3x-y=7, x+4y= 11 using cramers rule
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answer:Let us denote then by D, D(x) & D(y).
D is (3 -1 second row 1 4)
(3*4) - (1*(-1)) = 12+1=13
D(x) is (7 -1 and 11 4 in the second row)
(7*4 -(11*(-1))=28+11=39
D(y) is (3 7 1 11 in the second row)
33–7=26
Now, x=39/13=3
y=26/13=2
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