(3x+y-7z) ^2 evaluate using identity
Answers
Answered by
0
Step-by-step explanation:
(3x + y -7z)²
= (3x)² + (y)² + (-7z)² + (2× 3x × y) +(2×y×-7z)+(2×3x×-7z)
= 9x² +y²+49z² +6xy -14yz-42xz ----Ans
Similar questions