Question

3x+y=8 and x+y=6
$3x + y =8 andx + y = 6$
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Answer 1

Answer:

X=1 y=5

Step-by-step explanation:

3x+y=8

3x=8-y

x=8-y/3

x+y=6

(8-y/3)+y=6

8-y+3y/3=6

8+2y/3=6

8+2y=18

2y=18-8

2y=10

Y=10/2

Y=5

X=8-5/3

X=3/3

X=1

Answer 2

Answer

$\sf \dashrightarrow 3x + y = 8 \: \: --- (i)$

$\sf \dashrightarrow x + y = 6 \: \: --- (ii)$

By first equation,

$\sf \dashrightarrow 3x + y = 8$

$\sf \dashrightarrow 3x = 8 - y$

$\sf \dashrightarrow x = \dfrac{8 - y}{3}$

Now, let's find the value of y by second equation.

$\sf \dashrightarrow x + y = 6$

$\sf \dashrightarrow \dfrac{8 - y}{3} + y = 6$

$\sf \dashrightarrow \dfrac{8 - y + 3y}{3} = 6$

$\sf \dashrightarrow \dfrac{8 + 2y}{3} = 6$

$\sf \dashrightarrow 8 + 2y = 6 \times 3$

$\sf \dashrightarrow 8 + 2y = 18$

$\sf \dashrightarrow 2y = 18 - 8$

$\sf \dashrightarrow 2y = 10$

$\sf \dashrightarrow y = \dfrac{10}{2}$

$\sf \dashrightarrow y = 5$

Now, let's find the value of x by first equation.

$\sf \dashrightarrow 3x + y = 8$

$\sf \dashrightarrow 3x + 5 = 8$

$\sf \dashrightarrow 3x = 8 - 5$

$\sf \dashrightarrow 3x = 3$

$\sf \dashrightarrow x = \dfrac{3}{3}$

$\sf \dashrightarrow x = 1$

Hence, the values of x and y are 1 and 5 respectively.