Question

3x-y ,x-3y solve by substitution method​

Answer 1

Answer:

3 (3x-y)

1 (x-3y)

6x-3y=0

x-3y=0

7x=0

x=0/7=0

put value of x

3 (0)-y=0

-y=0

Answer 2

$\huge{\mathfrak{\underline{Question}}}$

$\large{\mathsf{Solve \: the \: equation \: by \: substition \: method \: 3x-y = 0 \: and \: x-3y =0}}$

$\huge{\mathfrak{\underline{Step-By-Step \: Explanation}}}$

$\large{\sf{3x-y=0......(1)}}$

$\large{\sf{x-3y=0...(2)}}$

$\large{\sf{x-3y=0 }}$

$\large{\mathsf{x = 3y }}$

put value of x in equation 1

$\large{\mathsf{3(3y)-3y=0}}$

$\large{\sf{9y -3y = 0}}$

$\large{\sf{6y = 0}}$

$\large{\sf{y = 0 }}$

$\rule{200}{2}$

Put value of y in equation 2

$\large{\sf{x-3(0)=0}}$

$\large{\sf{x-0=0}}$

$\large{\sf{x=0}}$

$\rule{200}{2}$