Question

(3x-y+z)^2 Expand using identities

Answer 1

Answer:

(3x-2y+z)^2

(3x)^2+(-2y)^2+(z)^2+2×3x×(-2y)+2x(-2y)×z+2×z×3x

=9x^2+4y^2+z^2-12xy-4yz+6xz

Answer 2

Answer:

9x^2+y^2+z^2-6xy-2yz+6xz

Step-by-step explanation:

so here we using the formula of (a-b+c)^2

which is a^2+b^2+c^2-2ab-2bc+2ac

so for this sum it goes like

(3x)^2+(y)^2+(z)^2- (2(3x(y))) - (2(y(z)))+ (2(3x(z)))

which is =

9x^2+y^2+z^2-6xy-2yz+6xz

hope this helps

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