Question

(3x-y+z) square ans this question​

Answer 1

Answer:

the answer of this question is 3xyz

Answer 2

Answer:

9x^2 + y^2 + z^2 - 6xy - 2yz + 6zx

Step-by-step explanation: (3x-y+z)^2

we know that

(a-b+c)^2= a^2 + b^2 + c^2 - 2ab - 2bc + 2ca

substituting value in the identity

(3x-y+z)^2=(3x)^2 + (y)^2 + (z)^2 - 2(3x)(y) - 2(y)(z) + 2(z)(3x)

=9x^2 + y^2 + z^2 - 6xy - 2yz + 6zx

hope this helps!!!

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