Math, asked by sd285011, 2 months ago

3x2-10x+3=0 find the roots of equations​

Answers

Answered by anshumanshaw1979
0

Answer:

Use the quadratic formula

=

±

2

4

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3

2

1

0

+

3

=

0

3x^{2}-10x+3=0

3x2−10x+3=0

=

3

a={\color{#c92786}{3}}

a=3

=

1

0

b={\color{#e8710a}{-10}}

b=−10

=

3

c={\color{#129eaf}{3}}

c=3

=

(

1

0

)

±

(

1

0

)

2

4

3

3

2

3

Answered by Anksn
1

Answer:

Applying BODMAS

Step-by-step explanation:

6-10x+3=0

9-10x=0

10x=9

x=9/10

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