3x2-10x+3=0 find the roots of equations
Answers
Answered by
0
Answer:
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
3
2
−
1
0
+
3
=
0
3x^{2}-10x+3=0
3x2−10x+3=0
=
3
a={\color{#c92786}{3}}
a=3
=
−
1
0
b={\color{#e8710a}{-10}}
b=−10
=
3
c={\color{#129eaf}{3}}
c=3
=
−
(
−
1
0
)
±
(
−
1
0
)
2
−
4
⋅
3
⋅
3
√
2
⋅
3
Answered by
1
Answer:
Applying BODMAS
Step-by-step explanation:
6-10x+3=0
9-10x=0
10x=9
x=9/10
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